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| [R] [1.22] Archer infinite; vs berserker only | |
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| Tweet Topic Started: Aug 29 2009, 07:49 AM (550 Views) | |
| windless | Aug 29 2009, 07:49 AM Post #1 |
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Mongrel-dono
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With berserker as opponent, archer's 6b 214b can be connected when the distance is not too close and there is a slight delay between the two moves. Thus the following loop becomes infinite near a wall: [jc (slight delay) jb 236b 5a*6 5b 6b (slight delay) 214b]*n ![]() |
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| Gabriel Roxas | Aug 29 2009, 08:05 AM Post #2 |
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Got his lines cut.
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Great combo, but I think it can't be done against a real opponent... and, second problem... you need the corner... |
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| Ssuusshhii | Aug 29 2009, 05:01 PM Post #3 |
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Mongrel-dono
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Uh... jc is amazingly easy to connect. It's not hard at all. And lots of Archer's moves already pushes an opponent far away. |
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8:33 AM Jul 11