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| jdege | Jun 24 2007, 01:51 AM |
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Elite member
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265 characters factors to 5*53. Which means that either characters don't encrypt to a constant number of digits, or each character or group of characters encrypts to five digits. But there are zero repetitions of the five-digit groups. Which would unlikely if each five-dgit group represented either a single character or a bigram. (And a five-digit group can't represent more than a bigram.) Which sends us back to characters not encrypting to constant numbers of digits. Which raises the question, how does the decipherer know how many digits make up a character? And which ends my patience for exploring this. Describe the cipher, provide plaintext/ciphertext pairs, so I can test to ensure that I understand how it works. And then encrypt ten plain text messages, each of >200 characters, with the same key, and I'll see if I can break it. |
| When cryptography is outlawed, bayl bhgynjf jvyy unir cevinpl. | |
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10:14 PM Nov 25