Viewing Single Post From: A New Challenge

Viewing Single Post From: A New Challenge
Revelation	Jun 24 2007, 09:58 AM
Administrator Posts: 386 Group: Admin Member #1 Joined: August 23, 2005	Welcome to the forum! This looks like a hard cipher. Some of the things I noticed: - it is possible to have an odd amount of numbers, so it can't be bigrams only - the last zeroes look like they are used to fill things up: 05000. Meaning they have no value. "This code is hard" has got 14 characters, excluding spaces. Inc it has got 17. This should be encrypted to 30 characters. Which thou canst not do with bigrams Then we've got the second with 28 characters, ex spaces. This should be encryped to 60 characters. So if the plain text is twice as long, the ciphertext is too. So I think we can jump to the conclusion that spaces are removed. Now we need to find the right connection between 14 and 30 characters Or there are just 2 spam characters with a plaintext with length 14, and with 28 characters 4 spam characters and we do have a bigram
	RRRREJMEEEEEPVKLWENFNVJKEEEEEAOLKAFKLXCFZAASDJXZTTTTTTTLSIOWJXMOKLAFJNNKFNXN RAGRBAQEMHIGDJVDSEOXVIYCELFHWLELJFIENXLRATALSJFSLCYTKLASJDKMHGOVOKAJDNMNUITN RRRRLJVEEEEECLYVYHNVPFTAEEEEEMWLMEIRNGLARWJAKJDFLWNTIERJMIPQWOTZEOCXKNUBNXCN RJIRPOWEANFUSNCZVDVZNMSFEKLOEPZLDKDJWSAAAAAAAOERHJCTNCKFRIMVKSOFOMKMANREWNBN RZUDRGXEEEEENFQIDVLQNCKNEEEEEDGLLLLLLAWIOSNCDARLODMTOEJXMILDFJROTKJSDNLVCZNN

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