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| catish10 | Aug 12 2007, 08:53 AM |
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Just registered
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Hi Thanks, I think I understand you. If its encrypted with a sub + vig = vig with a strange keyword! Have you broken it? If I am correct in thinking this is a sub+vig to break it I just need to treat it as a normal vig. So this gives me at least three different ways of attacking it! Can you confirm I am right with a keyword length of 6? Michelle
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| Double cipher challenge · Challenges | |




![]](http://209.85.122.85/static/1/pip_r.png)


3:57 PM Nov 25