Viewing Single Post From: Sometimes Things Are Easier Than They Look

Viewing Single Post From: Sometimes Things Are Easier Than They Look
jdege	Jun 24 2008, 04:17 PM
Elite member Posts: 263 Group: Admin Member #246 Joined: December 7, 2006	jdege Jun 9 2008, 06:27 PM There are 109 = 90 possibilities. In the cryptogram I was trying to solve, there were four digits that appeared doubled, leaving 6 5 = 30 possibilities. Yet again, I've gotten my statistics wrong. We're talking sets - order doesn't matter. 10 choose 2 = 10!/(2!8!) = (109)/(21) = 45 6 choose 2 = 6!/(2!4!) = (65)/(21) = 15
	When cryptography is outlawed, bayl bhgynjf jvyy unir cevinpl.

Sometimes Things Are Easier Than They Look · General