tidmiste

Aug 15 2008, 10:20 PM

Now for decryption. It's just as simple as long as you have both of the keys. You could separate it first by bigrams. So it would end up like:

Code:

 

70/64/40/61/64/40/63/12/86/43/18/28/64/30

Here's the kicker. The recipient would know immediately that this isn't the correct message, because there is no way any of the numbers would equal 12, so he could easily find out that it's a trigram in that instance, and then make the rest bigrams, changing the message to this:

Code:

 

70/64/40/61/64/40/63/128/64/31/82/86/43

Then, after this separation, all the numbers are sent through the equations, but in the y value instead of the x. Once you're done, it is easily readable.

For nulls in this example, you could use "18", because, even if they used the trigram rule above, it would rule out the number as a whole because no number going through those equations would be over 142.

Hopefully that clears things up.