Viewing Single Post From: Clarification

Viewing Single Post From: Clarification
osric	Jul 5 2009, 06:33 PM
Advanced Member Posts: 51 Group: Members Member #3,254 Joined: March 15, 2009	A single enciphering disk enables 26 different alphabets. If you imagine a disk with a mixed alphabet written around its perimeter and positioned in an annular ring with the normal alphabet inscribed, you have such a disk. It can be represented like this: ring: abcdefghijklmnopqrstuvwxyz disk: FROGSWALTZDUCKJIBVEXNYMPHQ This arrangement is the ‘F’ alphabet. Now if you rotate the disk one place anticlockwise you get: ring: abcdefghijklmnopqrstuvwxyz disk: ROGSWALTZDUCKJIBVEXNYMPHQF which is the ‘R’ alphabet. An enciphering machine with 2 disks can be set up in a number of ways. For example, each disk could have a different mixed alphabet, and be positioned within a ring marked with the normal alphabet: ring 1: abcdefghijklmnopqrstuvwxyz disk 1: FROGSWALTZDUCKJIBVEXNYMPHQ ring 2: abcdefghijklmnopqrstuvwxyz disk 2: WHYJUMPFOLDINGBRACKETSQVXZ To encipher ‘a’, you first look at ‘a’ in the ring of disk 1 and find ‘F’ on the disk. Then you look at ‘f’ on the ring of disk 2 and find ‘M’ on the disk. ‘M’ is the cipher equivalent. You can encipher every letter in this way and get the equivalent alphabet: abcdefghijklmnopqrstuvwxyz MCBPKQWLEZJTYDLOHSUVGXNRFA By moving disk 1 anticlockwise one step at a time, you will get 26 different alphabets. Then if you move disk 2 one step anticlockwise, and again move disk 1 a/c a step at a time you will get 26 more different alphabets. All told you will find 2626=676 different alphabets. Edited by osric*, Jul 5 2009, 06:40 PM.


Clarification · Chaocipher