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| Gerry StPierre | Jul 7 2009, 02:27 AM |
Just registered
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OK my confusion is coming from this statement in Progress Report #7 under the Experimenting with Cipher Disks heading about half-way down the page
And also the How to Construct a Cipher Disk page. Looking at the example completed cipher disk on the 'How To' page, you can see these two concentric alphabets outer: EINZVSPJFLUORXQTAKBHWMDGYC inner: WLCZFREDOHXMQYTVNJKSBPUIAG I had assumed that one of these two disks would be the plaintext, but that is not the case? Instead, a 'ring' of plaintext is also used? abcdefghijklmnopqrstuvwxyz EINZVSPJFLUORXQTAKBHWMDGYC WLCZFREDOHXMQYTVNJKSBPUIAG So in this example the current setting would be the 'EW' alphabet? The word 'too' would be encrypted as 'DNN'. If the outer disk is moved one position clockwise and the inner disk is moved one position anticlockwise after each letter then 'too' would encrypt as 'DAS'? Starting position 'EW' alphabet, t>H>D abcdefghijklmnopqrstuvwxyz EINZVSPJFLUORXQTAKBHWMDGYC abcdefghijklmnopqrstuvwxyz WLCZFREDOHXMQYTVNJKSBPUIAG Position after one move, 'CL' alphabet, o>X>A abcdefghijklmnopqrstuvwxyz CEINZVSPJFLUORXQTAKBHWMDGY abcdefghijklmnopqrstuvwxyz LCZFREDOHXMQYTVNJKSBPUIAGW Position after two moves, 'YC' alphabet, o>R>S abcdefghijklmnopqrstuvwxyz YCEINZVSPJFLUORXQTAKBHWMDG abcdefghijklmnopqrstuvwxyz CZFREDOHXMQYTVNJKSBPUIAGWL I realize that the whole mystery is what type of device the chaocipher is. But is the working assumption that there is a third fixed alphabet that would be the starting plaintext? By the way, I love the term 'anticlockwise' |
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| Clarification · Chaocipher | |
5:56 AM Nov 27
