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Challenge #3 Thread
Topic Started: Jul 23 2014, 08:31 PM (207 Views)
Violet Baudelaire
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Hi.
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Duncan Quagmire
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So, we number 1 to 4 or something. Any preference in terms of where we go in order?
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Esme Squalor
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Well I guess it's our turn for everyone to take the night off?
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Violet Baudelaire
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Looks like it's just Esme, Duncan, me, and soon Phil?

Making up an order is kind of a crapshoot. Whoever goes against Kit might just be unlucky... Maybe we should wait for them to post theirs first?
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Esme Squalor
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Fiona's here too, maybe we should use her instead of Phil?
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Violet Baudelaire
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Oh, Fiona is here now, too!
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Duncan Quagmire
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We have five of seven so far, and we know Carmelita won't be here tonight. The only one we're missing is Monty.
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Esme Squalor
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Does anyone think they're going to do terrible in this no matter what? We can just swap that person so they're facing Kit.
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Fiona
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I think I can do well.
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Phil
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I'm okay sitting out if everyone wants to compete. My internet connection sometimes gets really slow anyway.
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Duncan Quagmire
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If only four are competing, I wouldn't mind sitting out. My eyes are killing me from looking at this forum so much. If all of us compete, I'll give my all and hopefully figure out the code before whoever I'm competing against.
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Violet Baudelaire
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Okay, Phil in, Fiona out, then?
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Violet Baudelaire
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Or Duncan :|
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Fiona
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Violet Baudelaire,Jul 24 2014
01:39:47 AM
Okay, Phil in, Fiona out, then?

Did you say it backwards?
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Esme Squalor
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Duncan can face Kit. I will be killing you with my eye purse afterwards.

Phil sits out.

Is that all right?
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Violet Baudelaire
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Yes lol.

So me, Fiona, Esme, and Duncan and Phil, handle yo biz. Haha.
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Duncan Quagmire
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I'll compete if he wants everyone present to compete.
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Violet Baudelaire
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Esme Squalor,Jul 23 2014
09:41:29 PM
Duncan can face Kit. I will be killing you with my eye purse afterwards.

Phil sits out.

Is that all right?

That's about as in as we can get it tonight, it seems.
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Fiona
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Want to just do alphabetical again?
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Duncan Quagmire
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Alright, let's hope we can beat them at whatever this codebreaking is.
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